Class 11 Statistics Notes · GSEB

Comparative Study of Mean, Median and Mode

Comparative Study of Mean, Median and Mode — choose the right average for the data, apply change-of-origin-and-scale rules, and use the empirical relation. GSEB Class 11 Statistics notes with a comparison table and solved sums.

Last updated: 5 Oct 2026

Notes

No Single Average Fits Every Problem

Words marked with a dotted underline carry the question they usually appear in — tap them to reveal it.

Each average carries its own applications and its own limitations — that is exactly why this chapter spends five topics building all of them. Among them, the mean : it is rigidly defined, uses every observation and — the property that matters most — it can be pushed around by algebra. Advanced statistical methods and cross-population comparisons all speak in means. That makes it the optimum average, not the automatic one.

Mean

For evenly spread data and every calculation that follows — GDP growth, class averages, combined groups.

Median

Agriculture, social sciences and qualitative data — education, skill, consumer satisfaction — anything not evenly distributed.

Mode

Business and consumer choice — restaurant dishes, readymade garments, footwear sizes: what sells the most.

Negative example:a hostel surveys 20 students' monthly expenses and reports the mean of ₹12,400 — because one student drives a car and spends ₹90,000. Nineteen students live near ₹8,500. The average was arithmetically right and practically useless; the median (₹8,500) would have told the truth.

Three Lenses on the Same Nine Numbers

Floors of nine buildings: 2, 10, 4, 1, 4, 8, 4, 2, 8. The same data, looked at three ways — each average is answering a different question.

0246810x = number of floorsx̄ = 4.78

x̄ = 43/9 = 4.78

Add them up and divide — nothing needs sorting. The balance point of the whole cloud sits at 4.78.

x̄ = 4.78M = 4Mo = 4same nine numbers, three different questions

What each lens is really asking

The mean asks “where does the whole cloud balance?” (no ordering needed). The median asks “where do I cut to get equal halves?” (ordering first). The mode asks “which value shows up most?” (grouping by repeats).

Where Each Average Shines

1.

x̄ = Σx / n — the sum spread evenly over every observation.

2.

Rigidly defined, based on all values, and suitable for further algebraic operations — the optimum average.

3.

Best for evenly spread data: marks, heights, daily sales of a uniform shop.

4.

Weak spot: heavily affected by a few very large or very small values.

Mean vs Median vs Mode — Side by Side

Six attributes that decide which average a question is quietly testing.
AspectMeanMedianMode
Best forEvenly spread data and algebraSkewed, open-ended or missing dataBusiness, commerce and consumer choice
Ordering neededNo — add and divideYes — arrange firstGrouping by repeats
Effect of extremesHeavily affectedBarely affectedNot affected
Open-ended classesCannot be computedThe only average availableNot available — needs the modal class limits
Rigidly definedYesNoNo
Transform y = bx + aȳ = b·x̄ + ab·M + ab·Mo + a

Choice of Average — The Routing Map

Five questions decide which average you are allowed to use. Tap a factor to follow its route.

y = bx + a applies to all three

Change of origin and scale hits the mean, the median and the mode identically — ȳ = b·x̄ + a, median(y) = b·M + a, mode(y) = b·Mo + a.

The five factors behind the routes

The book lists them plainly: (1) the nature of data, (2) the nature of the variable, (3) the purpose of the study, (4) the type of classification used, and (5) whether the average will be used for further statistical analysis.

Some Results Worth Remembering

All values equal

Ages 15, 15, 15, 15, 15 → x̄ = M = Mo = G = x̄w = 15. Every average agrees.

Evenly distributed

— symmetric data makes the three lenses land on one point.

Change of origin & scale

y = bx + a transforms all three the same way: ȳ = b·x̄ + a, b·M + a, b·Mo + a.

The chapter's headline identity

Empirical relation

Mo=3M−2xˉM_o = 3M - 2\bar{x}

Mean, median and mode are not strangers — in moderately skewed data they lock into this single relation (Karl Pearson). Remember any two, get the third.

Transform Rules in Action

Mean

Mean of x is 9 and y = x + 4 →

ȳ = x̄ + 4 = 9 + 4 = 13

The same shortcut exists for the other two — no re-sorting, no re-counting:

Median

Median of 10 observations is 14; double every observation →

M(y) = 2 × 14 = 28

Mode

Mode of salaries is ₹8,500; the company deducts 2% for a welfare fund → mode of the fund = ₹170

0.02 × 8500 = 170

Worked Example Gallery

Comparative Study — Solved Practicals

4 problems

Transform of the mean

Full question

(1) The mean of a variable x is 25. Find the mean of the variable obtained by first subtracting 3 from x and then dividing it by 2.

ȳ = (x̄ − 3) / 2 = (25 − 3) / 2

Mean of y = 11

  1. y is x with a change of origin (−3) and a scale (÷ 2).
  2. ȳ = (x̄ − 3) / 2.
  3. ȳ = (25 − 3) / 2 = 22 / 2 = 11.

Transform of the median

Full question

(2) The relation between price (p) of an item and its demand (d) is d = 50 − 2p. If the median of price is ₹ 11, find the mean of demand.

median(d) = 50 − 2(11) = 28

Median demand = 28 items

Even a negative b works — the rule does not care about the sign.

  1. d is a linear function of p with b = −2 and a = 50.
  2. Median(d) = 50 − 2 × median(p).
  3. 50 − 2(11) = 50 − 22 = 28.

Transform of the mode

Full question

(3) The mode of salaries of employees of a company is ₹ 8500. The company has decided to deduct 2% of each employee's salary for welfare fund. Find the mode for the amount of this fund.

mode(y) = 0.02 × 8500

Mode of the welfare fund = ₹170

  1. Fund = 0.02 × salary → b = 0.02, a = 0.
  2. Mode(fund) = 0.02 × mode(salary).
  3. 0.02 × 8500 = 170.

Three-lens comparison

Full question

Study the following data for a general comparison of mean, median and mode. x = No. of floors in the building, n = 9.

2, 10, 4, 1, 4, 8, 4, 2, 8

Find the mean, median and mode for the number of floors.

LensMethodAnswer
Mean(2 + 10 + 4 + 1 + 4 + 8 + 4 + 2 + 8) / 9 = 43/94.78
Median5th of 1, 2, 2, 4, 4, 4, 8, 8, 104
Modevalue with frequency 34

x̄ = 4.78 · M = 4 · Mo = 4 — same data, three questions

  1. Mean: no ordering needed — 43/9 = 4.78.
  2. Median: order → 1, 2, 2, 4, 4, 4, 8, 8, 10; 5th observation = 4.
  3. Mode: 4 appears three times — more than any other value.

The mean sits slightly above the middle because 10 pulls it up.

Quick Reference

⭐ Mo = 3M − 2x̄ · evenly spread ⇒ x̄ = M = Mo · x̄ ≥ G · P₅₀ = M = Q₂ = D₅

Mean, median and mode all obey the same change-of-origin-and-scale rule — y = bx + a turns ȳ into b·x̄ + a, M into b·M + a and Mo into b·Mo + a.

.

The mean divides nothing — P₅₀ = M = Q₂ = D₅ is the set of cuts that split the data into two equal halves.

Key Takeaways

Key Takeaways

  • No single average suits every problem — mean for evenly spread data and algebra, median for skewed/open-ended/missing data, mode for business and consumer choice.
  • The mean is the optimum average because it satisfies most requisites of a good average — optimum, not automatic.
  • Same nine floors seen three ways: x̄ = 4.78 (balance point), M = 4 (midpoint cut), Mo = 4 (tallest column).
  • Five factors route you to an average: nature of data, nature of variable, purpose, classification, and further analysis — rates go to GM, weights to the weighted mean.
  • y = bx + a applies to all three alike, and Mo = 3M − 2x̄ locks them into one relation.
  • So what: whenever a number is quoted as “the average”, ask which lens produced it — the hostel example shows a mean can be correct arithmetic and still mislead everyone.